IN MariaDB
MariaDB verfügt über eine SEQUENCE Storage Engine . Wenn Sie also MariaDB verwenden, sind alle Ihre Sequenzprobleme vorbei (oder haben gerade erst begonnen).
Folge von 10 Zahlen
select * from seq_1_to_10;
TABELLEN NICHT VERWENDEN
Folge von 10 Zahlen
select * from
(select 0 x union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A;
Folge von 100 Zahlen
select (t*10+u+1) x from
(select 0 t union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A,
(select 0 u union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) B
order by x;
Folge von 1000 Zahlen
select (h*100+t*10+u+1) x from
(select 0 h union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A,
(select 0 t union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) B,
(select 0 u union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) C
order by x;
Folge von 10000 Zahlen
select (th*1000+h*100+t*10+u+1) x from
(select 0 th union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A,
(select 0 h union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) B,
(select 0 t union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) C,
(select 0 u union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) D
order by x;
TABELLEN VERWENDEN
Folge von 10 Zahlen
use test
drop table if exists seq10;
create table seq10
(x int not null auto_increment primary key);
insert into seq10 values (),(),(),(),(),(),(),(),(),();
select * from seq10;
Folge von 100 Zahlen
use test
drop table if exists seq100;
create table seq100
(x int not null auto_increment primary key);
insert into seq100 values (),(),(),(),(),(),(),(),(),();
insert into seq100 values (),(),(),(),(),(),(),(),(),();
insert into seq100 values (),(),(),(),(),(),(),(),(),();
insert into seq100 values (),(),(),(),(),(),(),(),(),();
insert into seq100 values (),(),(),(),(),(),(),(),(),();
insert into seq100 select x + 50 from seq100;
select * from seq100;
Folge von 1000 Zahlen
use test
drop table if exists seq1000;
create table seq1000
(x int not null auto_increment primary key);
insert into seq1000 values ();
set @p= -1;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
set @p=@p+1; insert into seq1000 select x+power(2,@p) from seq1000 where (x+power(2,@p)) <= 1000;
select * from seq1000;
Folge beliebiger Zahlen (Beispiel: 3,5 Millionen)
use test
drop table if exists seq;
create table seq
(x int not null auto_increment primary key);
insert into seq values ();
set @maxseq = 3500000;
set @p = -1;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
set @p=@p+1; insert into seq select x+power(2,@p) from seq where (x+power(2,@p)) <= @maxseq;
select max(x),count(x) from seq;
IHRE AKTUELLE FRAGE
Mit der Sequenz 0..9
haben Sie die Sequenz mit der Tabelle verknüpft
select A.number,1-ISNULL(B.number) present from
(select 0 number union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A
left join numbers B using (number);
Ihre Beispieldaten mit der neuen Abfrage
mysql> drop table numbers;
Query OK, 0 rows affected (0.01 sec)
mysql> drop table if exists numbers;
Query OK, 0 rows affected, 1 warning (0.00 sec)
mysql> create table numbers (number int);
Query OK, 0 rows affected (0.02 sec)
mysql> insert into numbers values (3), (2), (9);
Query OK, 3 rows affected (0.01 sec)
Records: 3 Duplicates: 0 Warnings: 0
mysql> select A.number,1-ISNULL(B.number) present from
-> (select 0 number union select 1 union select 2 union select 3 union select 4 union
-> select 5 union select 6 union select 7 union select 8 union select 9) A
-> left join numbers B using (number);
+--------+---------+
| number | present |
+--------+---------+
| 0 | 0 |
| 1 | 0 |
| 2 | 1 |
| 3 | 1 |
| 4 | 0 |
| 5 | 0 |
| 6 | 0 |
| 7 | 0 |
| 8 | 0 |
| 9 | 1 |
+--------+---------+
10 rows in set (0.00 sec)
mysql>
VERSUCHE ES !!!
range(10,20)
Mit MySQL 8.0, MariaDB 10.2 und späteren Versionen können Sie rekursive CTEs verwenden.
Sie können dies natürlich ändern, um den Startwert, den Schritt und den Endwert Ihrer Wahl zu verwenden.
Für die zweite Frage ist es dann trivial, das Obige zu erweitern (mit Inspiration aus einem Teil von Ronaldos Antwort):
Bearbeiten:
In MariaDB 10.3 wurden Sequenzobjekte eingeführt (wie im SQL-Standard definiert und z. B. im Oracle-RDBMS). Diese sind für diese spezielle Frage nicht hilfreich, da die Werte in der Datenbank gespeichert sind. Die Funktion kann jedoch in anderen sequenzbezogenen Anwendungsfällen hilfreich sein.
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