Schnittpunkt von zwei Listen Python
>>> a = [1,2,3,4,5]
>>> b = [1,3,5,6]
>>> list(set(a) & set(b))
[1, 3, 5]
batman_on_leave
>>> a = [1,2,3,4,5]
>>> b = [1,3,5,6]
>>> list(set(a) & set(b))
[1, 3, 5]def intersection(lst1, lst2):
lst3 = [value for value in lst1 if value in lst2]
return lst3
# Driver Code
lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69]
lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26]
print(intersection(lst1, lst2)) import numpy as np
recent_coding_books = np.intersect1d(recent_books,coding_books)# Python program to illustrate the intersection
# of two lists in most simple way
def intersection(lst1, lst2):
lst3 = [value for value in lst1 if value in lst2]
return lst3
# Driver Code
lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69]
lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26]
print(intersection(lst1, lst2))
# intersection of two lists (lst1 & lst2)
In [1]: x = ["a", "b", "c", "d", "e"]
In [2]: y = ["f", "g", "h", "c", "d"]
In [3]: set(x).intersection(y)
Out[3]: {'c', 'd'}
# has_intersection = bool(set(x).intersection(y)) -> True