>>> def fib(n): # write Fibonacci series up to n
... """Print a Fibonacci series up to n."""
... a, b = 0, 1
... while a < n:
... print(a, end=' ')
... a, b = b, a+b
... print()
...
>>> # Now call the function we just defined:
... fib(2000)
0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597#fibonacci series is special type of sequence
#fibonacci series is somethinng liket this-->
#0,1,1,2,3,5,8,13,21,34,55,89.......
#addition of former two succesive number results in the third element.
#in simple way as given in above series that 0,1,1--> where 0+1=1 e,i; 1
#example: 2,3,5 addition of 2 and 3 results in latter element in sequence e,i 5
8,13,21 : 8 + 13=21
34,55,89: 34 + 55=89#program to find the fibonacci series
n=int(input('Enter the number of terms in the Fibonacci series :'))
f,s=0,1
print('Fibonacci series =',f,s,sep=',',end=',')
for i in range(3,n+1):
nxt=f+s
print(nxt,end=',')
f,s=s,nxt
#output
Enter the number of terms in the Fibonacci series :7
Fibonacci series =,0,1,1,2,3,5,8,
________________________________________________________________________________
Enter the number of terms in the Fibonacci series :10
Fibonacci series =,0,1,1,2,3,5,8,13,21,34,
________________________________________________________________________________
Enter the number of terms in the Fibonacci series :4
Fibonacci series =,0,1,1,2, 1, 1, 2, 3, 5, 8
#include <stdio.h>
void main()
{
int s1=0,s2=1; //initializing first two numbers
int nextNum=0,SumUpto=0;
printf("\n\n\tPlease enter number up to which print Fibonacci series is required \t");
scanf("%d",&SumUpto);
//here assuming user will enter value more than 1
//printing first two numbers
printf("\n\tfibbonacci Series up to %d is ",SumUpto);
printf("\n\n\t%d %d",s1,s2);
for(nextNum=2;nextNum<=SumUpto;)
{
s1=s2;
s2=nextNum;
printf(" %d",nextNum);
nextNum=s1+s2;
}
}// FIBONACCI SERIES
// 0 1 1 2 3 5 8 13
let number = 7;
// let a=0,b =1,next;
let a=-1,b=1,next;
for(let i=1;i<=number;i++){
next= a + b;
a = b;
b = next
console.log(next)
}