Wie man das Array in Python umgeht
a = [1,2,3,4]
a = a[::-1]
print(a)
>>> [4,3,2,1]
Helpless Hyena
a = [1,2,3,4]
a = a[::-1]
print(a)
>>> [4,3,2,1]>>> the_list = [1,2,3]
>>> reversed_list = the_list.reverse()
>>> list(reversed_list)
[3,2,1]
OR
>>> the_list = [1,2,3]
>>> the_list[::-1]
[3,2,1]# method 1
arr = [11, 22, 33, 44, 55]
res = arr[::-1]
print("Reversed array:",res) #Reversed array: [5, 4, 3, 2, 1]
#method 2
arr = [11, 22, 33, 44, 55]
arr.reverse()
print("After reversing Array:",arr) #After reversing Array: [55, 44, 33, 22, 11]
#method 3
arr = [12, 34, 56, 78]
result=list(reversed(arr))
print("Resultant new reversed Array:",result) #Resultant new reversed Array: [78, 56, 34, 12]>>> L = [0,10,20,40]
>>> L[::-1]
[40, 20, 10, 0]>>> array=[0,10,20,40]
>>> for i in reversed(array):
... print(i)#The original array
arr = [11, 22, 33, 44, 55]
print("Array is :",arr)
res = arr[::-1] #reversing using list slicing
print("Resultant new reversed array:",res)