var secondMax = function (){
var arr = [20, 120, 111, 215, 54, 78]; // use int arrays
var max = Math.max.apply(null, arr); // get the max of the array
arr.splice(arr.indexOf(max), 1); // remove max from the array
return Math.max.apply(null, arr); // get the 2nd max
};
const array = [32, 523, 5632, 920, 6000];
let largestNum = array[0];
let secondLargestNum = 0;
for(let i = 1; i < array.length; i++) {
if(array[i] > largestNum) {
secondLargestNum = largestNum;
largestNum = array[i];
}
if else (array[i] !== largestNum && array[i] > secondLargestNum) {
secondLargestNum = array[i];
}
};
console.log("Largest Number in the array is " + largestNum);
console.log("Second Largest Number in the array is " + secondLargestNum);
/* Explanation:
1) Initialize the largestNum as index of arr[0] element
2) Start traversing the array from array[1],
a) If the current element in array say arr[i] is greater
than largestNum. Then update largestNum and secondLargestNum as,
secondLargestNum = largestNum
largestNum = arr[i]
b) If the current element is in between largestNum and secondLargestNum,
then update secondLargestNum to store the value of current variable as
secondLargestNum = arr[i]
3) Return the value stored in secondLargestNum.
*/
const max = arr => Math.max(...arr);['20','120','111','215','54','78'].sort(function(a, b) { return b - a; })[1];
// '120'
var secondMax = function (){
var arr = [20, 120, 111, 215, 54, 78]; // use int arrays
var max = Math.max.apply(null, arr); // get the max of the array
arr.splice(arr.indexOf(max), 1); // remove max from the array
return Math.max.apply(null, arr); // get the 2nd max
};function largestOfFour(mainArray) {
return mainArray.map(function (subArray){
return subArray.reduce(function (previousLargestNumber, currentLargestNumber) {
return (currentLargestNumber > previousLargestNumber) ? currentLargestNumber : previousLargestNumber;
}, 0);
});
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);