Array.prototype.equals = function(arr2) {
return (
this.length === arr2.length &&
this.every((value, index) => value === arr2[index])
);
};
[1, 2, 3].equals([1, 2, 3]); // true
[1, 2, 3].equals([3, 6, 4, 2]); // false// THE PROBLEM:
const firstArray = ["cookies", "milk", "chocolate"]
const secondArray = ["cookies", "milk", "chocolate"]
console.log(firstArray == secondArray) // always returns FALSE
// THE SOLUTION:
if(JSON.stringify(firstArray) === JSON.stringify(secondArray)){
console.log("firstArray is the same as the secondArray")
} else {
console.log("firstArray is different from the secondArray")
}let arr1 = [1, 4, 7, 4, 2, 3];
let arr2 = [1, 2, 3, 4, 7, 18];
const is_same = arr1.length == arr2.length &&
(arr1.every((currElem)=>{
if(arr2.indexOf(currElem)> -1){
return (currElem == arr2[arr2.indexOf(currElem)]);
}return false
})
)
console.log(is_same)const arr1 = [1, 2, 3];
const arr2 = [1, 3, 3];
if (arr1.length !== arr2.length) return console.log("false");
for (let i = 0; i < arr1.length; i++) {
for (let j = 0; j < arr2.length; j++) {
if (arr1[i] === arr2[j]) {
console.log("yes match", arr1[i], arr2[j]);
continue;
}
console.log("no match", arr1[i], arr2[j]);
}
}