function removeDuplicateCharacters(string) {
return string
.split('')
.filter(function(item, pos, self) {
return self.indexOf(item) == pos;
})
.join('');
}
console.log(removeDuplicateCharacters('baraban'));String arr[] = {"12341234abc", "1234foo1234", "12121212", "111111111", "1a1212b123123c12341234d1234512345"};
String regex = "(\\d+?)\\1";
Pattern p = Pattern.compile(regex);
for (String elem : arr) {
boolean noMatchFound = true;
Matcher matcher = p.matcher(elem);
while (matcher.find()) {
noMatchFound = false;
System.out.println(elem + " got repeated: " + matcher.group(1));
}
if (noMatchFound) {
System.out.println(elem + " has no repeation");
}
}
/* Time complexity of solution: O(n) */
const getRepeatedChars = (str) => {
const chars = {};
for (const char of str) {
chars[char] = (chars[char] || 0) + 1;
}
return Object.entries(chars).filter(char => char[1] > 1).map(char => char[0]);
}
getRepeatedChars("aabbkdndiccoekdczufnrz"); // ["a", "b", "c", "d", "k", "n", "z"]const text = 'abcda'.split('')
text.some( (v, i, a) => {
return a.lastIndexOf(v) !== i
}) // trueconst getRepeatedChars = (str) => {
let result = [];
str.map(each => {
let repeatedChars = 0;
for (let i = 0; i < each.length - 1; i++) {
if (each[i] === each[i + 1] && each[i] !== each[i - 1]) {
repeatedChars += 1;
}
}
result.push(repeatedChars);
});
return result;
};
getRepeatedChars(["aaabbbkdnndicccoekdczufnrz", "awsfgds"]); // [4, 0]