“Bild -Upload im PHP -Code mit Datenbanken” Code-Antworten

Laden Sie Bilder PHP MySQL hoch hoch

$filename = $_FILES['image']['name'];
function uploadFiles($filename){
    $ext = strtolower(pathinfo($filename, PATHINFO_EXTENSION));
    $filetmp = $_FILES['avatar']['tmp_name'];
  	..........
    ..........
    $target = $path.basename($filename);
    $upload = move_uploaded_file($filetmp,$target);

    if(!$upload){
      	$errors[] = 2;
    } 
}
Vivacious Vicuña

Bild -Upload im PHP -Code mit Datenbanken

$file = file(1000,100000)."-".$_FILES['file']['name'];
    $file_loc = $_FILES['file']['tmp_name'];
 $file_size = $_FILES['file']['size'];
 $file_type = $_FILES['file']['type'];
 $folder="uploads/";
sourav attri

IMG -Upload in PHP


                if(isset($_FILES['image']))
                {
                    $img_name = $_FILES['image']['name'];      //getting user uploaded name
                    $img_type = $_FILES['image']['type'];       //getting user uploaded img type
                    $tmp_name = $_FILES['image']['tmp_name'];   //this temporary name is used to save/move file in our folder.
                    
                    // let's explode image and get the last name(extension) like jpg, png
                    $img_explode = explode(".",$img_name);
                    $img_ext = end($img_explode);   //here we get the extension of an user uploaded img file

                    $extension= ['png','jpeg','jpg','gif']; //these are some valid img extension and we are store them in array.
                
kinjal suryavanshi

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