PHP JSON_DECODE
$personJSON = '{"name":"Johny Carson","title":"CTO"}';
$person = json_decode($personJSON);
echo $person->name; // Johny Carson
Grepper
$personJSON = '{"name":"Johny Carson","title":"CTO"}';
$person = json_decode($personJSON);
echo $person->name; // Johny Carson//"[{\"name\": \"bill\", \"score\": 0.7948127388954163}, {\"name\": \"john\", \"score\": 0.782698392868042}]";
//for json in above format try this
$r=json_decode(stripcslashes(trim($response,'"')));<?php
$json = '{"firstName":"Peter","lastName:":"Silva","age":23}';
$personInfo = json_decode(json);
echo $personInfo->age;
?>/** Checks if JSON and returns decoded as an array, if not, returns false,
but you can pass the second parameter true, if you need to return
a string in case it's not JSON */
function tryJsonDecode($string, $returnString = false) {
$arr = json_decode($string);
if (json_last_error() === JSON_ERROR_NONE) {
return $arr;
} else {
return ($returnString) ? $string : false;
}
}You have to use preg_replace for avoiding the null results from json_decode
here is the example code
$json_string = stripslashes(html_entity_decode($json_string));
$bookingdata = json_decode( preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $json_string), true );