So überprüfen Sie eine sogar oder ungerade Zahl in PHP
$num = 85;
if($num % 2 == 0){
echo "this is even number";
}else{
echo "this is odd number";
}
nk
$num = 85;
if($num % 2 == 0){
echo "this is even number";
}else{
echo "this is odd number";
}
$num = 34;
if ($num % 2 == 0) {
print "It's even";
}$number = 15;
if ($number % 1 == 0) {
echo "It's even";
}else{
echo "oneven";
}