“Boto3 Python S3” Code-Antworten

Python3 Boto3 geben S3 Objekt ein

# Boto 2.x
from boto.s3.key import Key
key = Key('hello.txt')
key.set_contents_from_file('/tmp/hello.txt')

# Boto 3
s3.Object('mybucket', 'hello.txt').put(Body=open('/tmp/hello.txt', 'rb'))
Impossible Impala

Boto3 S3

import logging
import boto3
from botocore.exceptions import ClientError
import os


def upload_file(file_name, bucket, object_name=None):
    """Upload a file to an S3 bucket

    :param file_name: File to upload
    :param bucket: Bucket to upload to
    :param object_name: S3 object name. If not specified then file_name is used
    :return: True if file was uploaded, else False
    """

    # If S3 object_name was not specified, use file_name
    if object_name is None:
        object_name = os.path.basename(file_name)

    # Upload the file
    s3_client = boto3.client('s3')
    try:
        response = s3_client.upload_file(file_name, bucket, object_name)
    except ClientError as e:
        logging.error(e)
        return False
    return True
Powerful Partridge

Python Boto3 Put_Object zu S3

file = open(r"/tmp/" + filename)
response = s3.meta.client.Bucket('<bucket-name>').put_object(Key='folder/{}'.format(filename), Body=file)
Impossible Impala

Boto3 Python S3

response = client.abort_multipart_upload(
    Bucket='string',
    Key='string',
    UploadId='string',
    RequestPayer='requester',
    ExpectedBucketOwner='string'
)
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