“Hinzufügen von Rollen Discord Py” Code-Antworten

diskord.py wie man einem Benutzer eine Rolle gibt

# If ctx is not defined and you are handling a message, use this code
ctx = await bot.get_context(message)

# This is the code needed to give a user a role
member = ctx.message.author # Member object that you want to add the role to
role = discord.utils.get(lambda role: role.name == "Role Name", ctx.guild.roles) # The role object
await member.add_roles(role) # Adds the role to the member
The Angriest Crusader

Fügen Sie Rollen -Zwietracht hinzu .py

member = message.author
var = discord.utils.get(message.guild.roles, name = "role name")
member.add_role(var)
Tyrannicodin16

Erstellen Sie eine Rolle mit Discord.py

@client.command(aliases=['make_role'])
@commands.has_permissions(manage_roles=True) # Check if the user executing the command can manage roles
async def create_role(ctx, *, name):
	guild = ctx.guild
	await guild.create_role(name=name)
	await ctx.send(f'Role `{name}` has been created')
HelloWorld

Hinzufügen von Rollen Discord Py

# If you need this in a bot command
@discord.ext.commands.command()
async def online(ctx):
  	guild_id = ctx.guild.id # the guild id where the command has been called
    role = discord.utils.get(bot.get_guild(guild_id).roles, id ="""The Id of the role you search""")
    await member.add_roles(role) # The role gets added to a given Member
meppi

Hinzufügen von Rollen Discord Py

# If you need this in a bot command
@bot.command()
async def online(ctx):
    role = discord.utils.get(bot.get_guild(ctx.guild.id).roles, id ="Role ID")
    await member.add_roles(role)
Happy Horse

Fügen Sie Rollen -Zwietracht hinzu .py


from discord.ext import commands
from discord.utils import get

bot = commands.Bot(command_prefix='!')

@bot.command(pass_context=True)
@commands.has_role("Admin") # This must be exactly the name of the appropriate role
async def addrole(ctx):
    member = ctx.message.author
    role = get(member.server.roles, name="Test")
    await bot.add_roles(member, role)
Wide-eyed Wildebeest

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