Tagesunterschied zwischen zwei Daten in Python
from datetime import date
d0 = date(2017, 8, 18)
d1 = date(2017, 10, 26)
delta = d1 - d0
print(delta.days)
Real Rhinoceros
from datetime import date
d0 = date(2017, 8, 18)
d1 = date(2017, 10, 26)
delta = d1 - d0
print(delta.days)from datetime import datetime, timedelta
def date_range(start, end):
delta = end - start # as timedelta
days = [start + timedelta(days=i) for i in range(delta.days + 1)]
return days
start_date = datetime(2008, 8, 1)
end_date = datetime(2008, 8, 3)
print(date_range(start_date, end_date))import pandas
pandas.date_range(sdate,edate-timedelta(days=1),freq='d')from datetime import date
startDate = date(2021, 7, 19)
endDate = date(2021, 11, 12)
delta = startDate - endDate
print(delta.days)# If you convert all your date to `datetime.date`, you can write the following:
if start <= date <= end:
print("in between")
else:
print("No!")