Pyhon sortiert eine Liste von Tupeln
sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1])
Thankful Tiger
sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1])my_list =[("p",23),("m",2),("q",19),("f",77),("a",50),]
# we will use the 'sort' method
my_list.sort(reverse = True, key = lambda t: t[1])
# the result will be
my_list
[('f', 77), ('a', 50), ('p', 23), ('q', 19), ('m', 2)]# Python program to sort a list of tuples by the second Item
# Function to sort the list of tuples by its second item
def Sort_Tuple(tup):
# Getting length of list of tuples
lst = len(tup)
for i in range(0, lst):
for j in range(0, lst-i-1):
if (tup[j][1] > tup[j + 1][1]):
temp = tup[j]
tup[j]= tup[j + 1]
tup[j + 1]= temp
return tuplst = [("val1", 2), ("val1", 1)]
lst.sort()
print(lst)
# Output: [('val1', 1), ('val2', 2)]