“Sqlite3 Python” Code-Antworten

Python Sqlite

import sqlite3
import os.path

#Connection to the DB
try:
    # Make sure to find the file.db in the script directory
    BASE_DIR = os.path.dirname(os.path.abspath(__file__)) 
    db_path = os.path.join(BASE_DIR, "sqlite.db")
    conn = sqlite3.connect(db_path)

except sqlite3.Error as error:
    print("Failed to read data from sqlite table", error)



# Execute query on the sqlite DB
cur = conn.cursor()
cur.execute("SELECT * FROM tasks")

# Print everything from a table
rows = cur.fetchall()
for row in rows:
        print(row)
    
# Update field 
conn.execute("""UPDATE tasks SET name = \'jhon\'
 where id = 1""")

# close the DB connection 
conn.close()
Maxime Merveille

So installieren Sie SQLite3 in Python

if you are using python3, sqlite3 is built in into it.
Tahsin

So installieren Sie SQLite3 Python

pip install db-sqlite3
Uptight Unicorn

So installieren Sie SQLite3 in Python

#!/usr/bin/python

import sqlite3

conn = sqlite3.connect('test.db')

print "Opened database successfully";
OSP PRO

Sqlite3 Python

import sqlite3
from sqlite3 import Error


def create_connection(db_file):
    """ create a database connection to the SQLite database
        specified by db_file
    :param db_file: database file
    :return: Connection object or None
    """
    conn = None
    try:
        conn = sqlite3.connect(db_file)
    except Error as e:
        print(e)

    return conn


def create_project(conn, project):
    """
    Create a new project into the projects table
    :param conn:
    :param project:
    :return: project id
    """
    sql = ''' INSERT INTO projects(name,begin_date,end_date)
              VALUES(?,?,?) '''
    cur = conn.cursor()
    cur.execute(sql, project)
    conn.commit()
    return cur.lastrowid


def create_task(conn, task):
    """
    Create a new task
    :param conn:
    :param task:
    :return:
    """

    sql = ''' INSERT INTO tasks(name,priority,status_id,project_id,begin_date,end_date)
              VALUES(?,?,?,?,?,?) '''
    cur = conn.cursor()
    cur.execute(sql, task)
    conn.commit()
    return cur.lastrowid


def main():
    database = r"C:\sqlite\db\pythonsqlite.db"

    # create a database connection
    conn = create_connection(database)
    with conn:
        # create a new project
        project = ('Cool App with SQLite & Python', '2015-01-01', '2015-01-30');
        project_id = create_project(conn, project)

        # tasks
        task_1 = ('Analyze the requirements of the app', 1, 1, project_id, '2015-01-01', '2015-01-02')
        task_2 = ('Confirm with user about the top requirements', 1, 1, project_id, '2015-01-03', '2015-01-05')

        # create tasks
        create_task(conn, task_1)
        create_task(conn, task_2)


if __name__ == '__main__':
    main()
Code language: Python (python)
Cesar Díaz

Python Sqlite3

filelist sqllite
Tame Tarsier

Ähnliche Antworten wie “Sqlite3 Python”

Fragen ähnlich wie “Sqlite3 Python”

Weitere verwandte Antworten zu “Sqlite3 Python” auf Python

Durchsuchen Sie beliebte Code-Antworten nach Sprache

Durchsuchen Sie andere Codesprachen

Shell/Bash
C#
C++
C
CSS
HTML
Java
JavaScript
Objective-C
PHP
Python
Sql
Swift
Ruby
TypeScript
Go
Kotlin
Assembly
R
VBA
Scala
Rust
Dart
Elixir
Clojure
Haskell
Matlab
Erlang
Cobol
Fortran
Scheme
Perl
Groovy
Lua
Julia
Delphi
Abap
Lisp
Prolog
Pascal
ActionScript
Basic
Solidity
PowerShell
GDScript
Excel