PostgreSQL Zeigen Sie die Unterabfrage als JSON an
// joining 3 tables and nesting results as json, keys can be named arbitrarily
select
json_build_object(
'id', u.id,
'name', u.name,
'email', u.email,
'user_role_id', u.user_role_id,
'user_role', json_build_object(
'id', ur.id,
'name', ur.name,
'description', ur.description,
'duty_id', ur.duty_id,
'duty', json_build_object(
'id', d.id,
'name', d.name
)
)
)
from users u
inner join user_roles ur on ur.id = u.user_role_id
inner join role_duties d on d.id = ur.duty_id;
Wide-eyed Fox