“row_number äquivalent ms Access für sequentielle ID nach Gruppe (2)” Code-Antworten

row_number äquivalent ms Access für sequentielle ID nach Gruppe (2)

select g.CODE
     , count(*)-1 as C_NO
     , g.NAME
from MyTable as g
  left join MyTable as o
    on g.CODE = o.CODE
      and g.NAME >= o.NAME
group by g.CODE
       , g.NAME;