Wählen Sie die Anzahl der unterschiedlichen Werte SQL
SELECT COUNT (DISTINCT column-name) FROM table-name
Relieved Rook
SELECT COUNT (DISTINCT column-name) FROM table-nameSELECT COUNT(DISTINCT country)
FROM Customers;SELECT COUNT(DISTINCT program_name) AS Count,
program_type AS [Type]
FROM cm_production
WHERE push_number=@push_number
GROUP BY program_typeselect column_name, count(*) AS count FROM table_name GROUP BY column_name;SELECT a.*
FROM emails a
INNER JOIN
(SELECT email,
MIN(id) as id
FROM emails
GROUP BY email
) AS b
ON a.email = b.email
AND a.id = b.id;