Längste gemeinsame Präfixmethode 2
class Solution:
def longestCommonPrefix(self, strs):
result = []
for i in zip(*strs):
if len(set(i)) != 1:
break
result.append(i[0])
return "".join(result)
"""The zip() method returns a zip object, which is an iterator of tuples where
the first item in each passed iterator is paired together, and then the second item in
each passed iterator are paired together etc.
If the passed iterators have different lengths, the iterator with the least items
decides the length of the new iterator.
set() method is used to convert any of the iterable to sequence of iterable elements
with distinct elements, commonly called Set.
"""
Task = Solution()
print("3a. ",Task.longestCommonPrefix(["flower","flow","flight"]))
print("3b. ",Task.longestCommonPrefix(["dog","racecar","car"]))
Kingsley Atuba