Pfadsumme mit Python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.left = left
class Solution:
def hasPathSum(self, root: Optional[TreeNode], targetSum: int) -> bool:
if root == None:
return False
remain = targetSum - root.val
if remain == 0 and root.left == None and root.right == None:
return True
return self.hasPathSum(root.left, remain) or self.hasPathSum(root.right, remain)
Eol Nuha