Wie man einen Taschenrechner in Python erstellt
# Program make a simple calculator
# This function adds two numbers
def add(x, y):
return x + y
# This function subtracts two numbers
def subtract(x, y):
return x - y
# This function multiplies two numbers
def multiply(x, y):
return x * y
# This function divides two numbers
def divide(x, y):
return x / y
# This function exponents two numbers
def exponentiation(x, y):
return x ** y
# This function finds the floor division two numbers
def root(x, y):
return x // y
print("Select operation.")
print("1.Add")
print("2.Subtract")
print("3.Multiply")
print("4.Divide")
print("5.Exponential")
print("6.Floor Division")
while True:
# take input from the user
choice = input("Enter choice(1/2/3/4/5/6): ")
# check if choice is one of the four options
if choice in ('1', '2', '3', '4', '5', '6'):
num1 = float(input("Enter first number: "))
num2 = float(input("Enter second number: "))
if choice == '1':
print(num1, "+", num2, "=", add(num1, num2))
elif choice == '2':
print(num1, "-", num2, "=", subtract(num1, num2))
elif choice == '3':
print(num1, "*", num2, "=", multiply(num1, num2))
elif choice == '4':
print(num1, "/", num2, "=", divide(num1, num2))
elif choice == '5':
print(num1, "**", num2, "=", exponentiation(num1, num2))
elif choice == '6':
print(num1, "//", num2, "=", root(num1, num2))
# check if user wants another calculation
# break the while loop if answer is no
next_calculation = input("Let's do next calculation? (yes/no): ")
if next_calculation != "yes":
break
else:
print("Invalid Input")
Sleepy Skimmer
