“Java Lexographie” Code-Antworten

Java Lexographie

String myStr1 = "Hello";
String myStr2 = "Hello";
System.out.println(myStr1.compareTo(myStr2)); // Returns 0 because they are equal
/* An int value: 0 if the string is equal to the other string.
< 0 if the string is lexicographically less than the other string
> 0 if the string is lexicographically greater than the other string (more characters)*/