“Java versuchen zu fangen” Code-Antworten

Versuchen Sie, Java zu fangen

public class MyClass {
  public static void main(String[ ] args) {
    try {
      int[] myNumbers = {1, 2, 3, 4, 5, 6};
      System.out.println(myNumbers[10]);
    } catch (Exception e) {
      System.out.println("Something went wrong. check again");
    }
  }
}
 
Mr. Samy

Java versuchen zu fangen

import java.io.*;
import java.util.Scanner;
public class Test {
    public static void main(String args[]) throws Exception {

        String input;
        int ch1;
        float ch2;
        String ch3;

        Scanner one = new Scanner(System.in);

        input = one.nextLine();

        try {
            ch1 = Integer.parseInt(input);
            System.out.println("integer");
            return;
        } catch (NumberFormatException e) {


        }

        try {
            ch2 = Float.parseFloat(input);
            System.out.println("float");
            return;
        } catch (NumberFormatException e) {

        }
        try {
            ch3 = String.valueOf(input);
            System.out.println("String");
        } catch (NumberFormatException e) {

        }


    }
}
PallaviN

Java versuchen zu fangen

int midterm;
  System.out.printLn("Enter midterm grade");
  do
  { 
      try {
          string s = in.nextLine();
          midterm = Integer.parseInt(s);
          break;
      }
      catch (Exception e)
      {
          System.out.printLn("Couldn't parse input, please try again");
      }
  }
  while (true);
PallaviN

Java versuche fangen

try{
  //Code that is checked for error
} catch(Exception e){
  //Code runs when error is caught
}
Christina Zhang

Java versuchen ... Block fangen

class Main {
  public static void main(String[] args) {

    try {
      int divideByZero = 5 / 0;
      System.out.println("Rest of code in try block");
    }

    catch (ArithmeticException e) {
      System.out.println("ArithmeticException => " + e.getMessage());
    }
  }
}
SAMER SAEID

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